? "!$# " %#&('"'() *,+.-0/0 E 0 Ω 9 ) Determnare l bpolo equalente d Norton a morsett. ) S dca quale delle seguent affermazon è corretta, gustfcando la rsposta: a) l bpolo è passo, b) l bpolo è controllable n corrente. 00 Ω 0 V 0 Ω %7698:<;7+ TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto =>@?C?ED&FHGJIKG9>L?M NPO0FHQ@MR?RS<I0D&TUOV?M(W@?Q<GXMRGYNGXNPZ?RZ[@O0>]\G^D&MMD^NOCTU?ROH\?"_XOC>@O0TUD&ZGXTÒ \?(ZO0>]N?RGX>@OHOH\@OC?"\[@O TUO0N?ENZUG9TU?7Mba O0cd[@?efD9MRO0>dZO Zg@O0e9O0>@?R>h\?ZjD&MÒ NOCTU?ROXklGme.e9OCTUGn[@>L_9O0>@OCTjDmZUG9TUOo\?ZUOC>]N?RGX>@OH\@Dqpsr&tO0\u[@>qTUO0N?ENZUG9TUOV\@D G9Z?ED&FHGxQ%G9?(Ijg@OHN[@MRMba D&MRZTUG TUD9FHGn\?cd[@O0NPZG W]?RQ%G9MGnNP?$g]DHMED NPO0T?Oy\?z[@>J_XOC>@O0TUD&ZGXTO\?$ICG9TUTO0>dZO {NOCW@W%OC>]OyQ@?MRG9ZUDmZUGd }Oy\?$[@>JTUO0N?NPZGXTO\@DJpsr9rn~g@F 00Ωow FHG9TjNPOCZPZ?lOsNZUTO0FH?\?zcd[@O0NPZUDHNOCTU?RO?MIKGXFHQ<GXTPZjD&FHOC>dZGHNUD&Tj oq]d9t?zdhcd[@o0mrmg \OCMNG9MG`_9OC>]OCTjDmZGXTO\?zICG9TUTO0>XZUO, 0 Ω 00Ω 0 Ω >]DeXG9MRZUDNOCFHQ@M?ƒS<I0DmZjDMDTUOKZUO Q<GdNN?D9FHGQ]TGIKOs\OCTUO IKGX>`?M<I0D&MEIKGXMRG\OCMMEDTOsNP?ENZUOC>@sDO0cd[@?efD9MRO0>dZO >@G9>^Q@?MG&ZUD&Z?lOyICG9MMRO0_9g@?ED&FHG`[@>^_9OC>]OCTjDmZGXTO\?NG9>]\]D 9 ( Q%OC_X>]D&FHG?]_XOC>@O0TUD&ZGXT? 00Ω I s V s D9MRMEDVS]_9[]TUD`NP?>@G&ZjD`ICG9FHO { $ˆ ŠDX\ [@>]Gn\OC?z\[]OZUD&_XMR?l>]G.\]D&M?E Is = 0 ŒOCT MEDVMOC_X_9O\?7~g]F MDHICG9TUTO0>XZUO>]OCMzTUO0N?NPZGXTO\@D c Q]D9T?zD] 00Ω G&ZZOC>]?D9F`G cd[@?>]\? 7 s. s. šœž f fÿjo f Ÿ š:š C : = s 00Ω p
w w O w O I s = 0 V s 00Ω G9Q@Q][@TO R eq = V s = V s I V s S 0Ω = 0Ω G eq = I s = V s 0 Ω }D&MEIKGXMR?ED&FHG`G9TjDo?MlemD&MG9TUO\O0Mz_9O0>@OCTjDmZUG9TUO\?$IKG9TUTUOC>dZOO0cd[@?efD9MRO0>dZO {I0D&MEIKG9MED&><\GVMEDHIKGXTTUOC>dZO\?ICG9TZGHIK?TUIC[@?RZG D&?lFHG9TjNOKZPZU? \OCMzW]?RQ%G9MGd 9 9 0V 00Ω I CC 0V 0V 00Ω ICC 0V 00Ω 0 ICC,G9TZGIK?TjIK[@?RZUD9>]\G`?lF`GXTUNOKZZ? N?ze.?OC>@OD9\ Dfe9O0TO[@>]D`ZUOC>]N?G9>@O\?"psr&t N[@MlTOsNP?ENPZG9TUO\@D = 0V 00Ω = 0. \@DHIK[@?$NP?lTU?I0DfemDoMED IKGXTTUOC>dZO\?zICG9TZG IK?TUIC[@?RZG IKO0TUI0DmZUD 00Ω"?lg<D cx[]?r>]\@?ijg@o9 =MIK?TjIK[@?RZGHO0cd[@?emD&MOC>dZO G9TZG9> ND9TUD]acX[]?R>]\@?\@DmZUG \@D@ I CC = 0 = 0( 0.) = eq G eq IKGX> eq = O G eq = D] " ~V ]=MzW@?Q%G9MG >@G9> 0 Ω Q]DXNN?e9G`?R>Ycd[]D9>XZUG?RM$NP[@GnIC?RTjIK[]?ƒZUG O0cd[@?efD9MRO0>dZO GXTPZUG9> g]dh[@>j_xoc>@o0tud&zg9tuo\?$icg9tuto0>xzuo>@g9> >.[@MRMGyOcd[@?>]\?<MDoNP[]DoICD&TjDmZZO0T?ENZU?I0D>@G9> Q]DXNNUDNPGXMRGQ%OCT,?RM<Q@TU?RFHGyOQ%OCT,?RM]ZO0T0GycX[<D9\TjD&>dZOy{[Z?M?R00D&><\GyMOIKGX>deXOC>@0?RGX>@?]\O0_9M? [Z?M?R00DmZUG9TU?lQ<O0TO0NQ@TU?RFHO0T>@OIKGXTTUOC>dZUOOZUOC>]N?RGX>@Os Wz t ª~V @=M$W@?RQ%G9MG IKGX>dZTUG9MMD9W@?RMO?R>JICG9TUTO0>XZUO?R>Jcd[]D&>dZUG]k]ICG9MMRO0_XD&><\GV[]>J_9OC>]OCTjDmZGXTO\?ICG9TUTO0>dZOZTjDH?zFHG9TjNPOCZPZU? MDxTUOKZÒ G&ZZO0>d[@ZUDxg]DxNG9M[@0?RGX>@O D&MOVGdNNOCTUemD&0?RGX>@OyQ@[@ O0NUNOCTUOy D9IC?RMFHOC>dZÒ e9o0t?rs<i0dmzud [Z?M?R00D&><\Gx?M(IK?TUIC[@?RZG O0cd[@?efD9MRO0>dZO GXTPZUG9> Os\ D9_9_9?[@>@_XOC>]\@Gy[@> _XOC>@O0TUD&ZGXTO\@? ICG9TUTO0>dZO?> Q<D&TjD&MMRO0MRGoDX\nOsNNG y«nunpo0>]\g G eq 0 NP? Q@[] VICD9MICG9MED&TUO k.gxmƒzutod9\ V I
Y PP "!$#. %#m(' '() *,+.-0/0 E V Conoscendo l alore delle arabl assegnate sul crcuto e sapendo che l bpolo assorbe 0 W determnare la tensone e la corrente del bpolo. V V %7698:<;7+ TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto V V V V V 0W/V=0 V V LKT LKT Defnz. d potenza LKI 0 Rsultato ŒOCT _9?[@>@_XOCTUOD9MzTU?N[@MRZUDmZUG`N?zOsNPO0_9[@GX>@GV?lQ<D9NUNP?l?>]\?EICD&Z?z?> S]_9[@TjD@kD9Q@Q@M?I0D&>]\GHTU?NQ%OKZPZU?RemD9F`O0>dZO9 $ˆ «$ˆ «OKS<>@?R0?RGX>@Oy\?lQ%G&ZUOC>@sD $ˆ G&ZZOC>]OC>]\G?MlTU?N[@MRZUDmZUGHT?Q<GXTPZjDmZUGV>@O0MRMba [@MƒZU?RF D`S]_X[@TjD`\@OCMzW@MGICICG ±( f. " f d š:œž s fÿjo f b f²: Ÿ f E³ V
Y!µ µ PP "!$#. %#m(' '() *,+.-0/0 TTENZIONE: Solgere a scelta l eserczo Ea oppure Eb Ea 6 Ω e e e ) Utlzzando l metodo dell anals nodale, determnare potenzal d nodo e, e, e rspetto al nodo d rfermento. ) determnare l alore della tensone ) determnare l alore della corrente g ) Determnare la potenza erogata dal generatore d tensone da V g 6 Ω Ω V V Ω %7698:<;7+ TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto =,Q%G&ZUOC>@0?D9MR? Os\ N?zQ%GXNUNPGX>@G NICT?e9O0TO?F`FHOs\?D&ZUD9F`O0>dZOyDHICD9[]NDH\O0MRMEDHQ@TUO0NOC>@sDV\@OC?_XOC>@O0TUD&ZGXT? \?zzuoc>]n?g9>@oztjdh?mz>@g\g \?ztu?ƒ O0T?FHOC>dZGHOs\x?l>]G.\@?"pO e e e = V e = V ª?FHD9>@Ocd[@?R><\?\@D I0D&MEIKG9MED&TUO?Mz>@G\G IKGX>x?MzFHOKZUG\Gn\OC?lQ%G&ZUOC>@0?D9MR?$\?z>@G\G e e + } 6Ω {{} Corr. R da 6Ω e Ω }{{} Corr. R da Ω ( + e e = 0 } Ω {{} Corr. R da Ω e 6 6 + e + e = 0 e + + = IKTU?Re.?ED&FHGVMEDH ˆ= D&Ml>@G\G } DVZUOC>]N?RGX>@O V e = 6V \]DmZUD \]D&MMD`\?R %O0TO0>@0DH\O0?zQ<G9ZO0>@C?ED&M?\O0Ml>@G\G O\@OCMz>@G\G^p,ŒOCTI0D&MEIKGXMD9TOMDHIKGXTTUOC>dZUO V = e e = ( ) = 6V g NICT?e.?D9F`G`[@>]D $ˆ D&Mz>@G\G^p \@DHIK[@? ( V 6V g = 6Ω g + e e 6Ω + e e 6Ω = 0 + ) + = ( + ) = 6Ω ¹ ŒOCTQ%G&ZUOCTyICD9MICG9MED&TUOoMED Q<G9ZOC>]0D OCTUG9_dDmZUDx\@D&M(_XOC>@O0TUD&ZGXTÒ \?(ZO0>]N?RGX>@O \@D >@O0ICO0NUND9T?G ICG9>@GdNICOCTU>@OoMED^IKGXTTUOC>dZO,g@?ED&FH?D9FHG MDIKGXTTUOC>dZUÖ Ijg@O DmZPZUTUDfeXOCTjND}ZjD&MO,_XOC>@O0TUD&ZGXTÖ \]D&MM:a D&MRZGe9OCTjNG?RM.W]DXNNG]km?>oFHG\GZUD9MRO}\@DDfeXOCTUO"[@>]DIKGX>.e9OC>]C?G9>@O V \OC?7_9O0>@OCTjDmZUG9TU?lIjg@OyMOC_9g]?MED`ZOC><NP?G9>@OV\@DJp G t OyMEDnIKGXTTUOC>dZOIjg@OVNZU?D9F`G Q%OCTICD9MICG9MED&TUO =>YZUD&M$FHG.\@G?RM7Q@TUG.\@G&ZPZUG MDHQ%G&ZUOC>@sD`OCTUG9_XD&ZUD V I \@D9TU ¹
,G9> [@>]DH ˆ= D&Ml>]G.\@G G9ZPZO0>@?ED&FHG I G + e e Ω + e e 6Ω = 0 e e {}}{{}}{ V 6V I G = Ω D`Q%G&ZO0>@0D`O0TGX_XDmZjDV\]D&Ml_9O0>@OCTjDmZUG9TUONUD&Tj Vcd[@?>]\? e e {}}{{}}{ V V 6Ω = 8 + 6 6 = + = Y!ºoµ "!$# " %#&('"'() *,+.-0/0 P G = V I = V = 0W TTENZIONE: Solgere a scelta l eserczo Ea oppure Eb Eb kω 0 kω ) Determnare la corrente he percorre l resstore R o e la potenza da esso dsspata. ) Determnare la potenza erogata dal generatore d tensone ) Determnare la potenza erogata dall amplfcatore operazonale V R o = kω %7698:<;7+ TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto ps ª?EIKGXTU\@?D9F`G?>@>]D9>@C?RZ[ZZGyIjg@O MEDIKGXTTUOC>dZO O0>XZUTUD9>dZO >@OC_XMR?]?R>@_XTOsNN?\?][]>`GXQ<O0TUD9C?G9>]D9MRO NZUO0NUNP?lFHGXTUNOKZZ?\O0e9OO0NUNOCTUO>.[@MMD >.[@MMDOIjg@O MEDZO0>]NP?G9>]O,ZUTUDcd[@O0_9M? 0kΩ kω a + out b V V out kω =MzQ%G&ZO0>@C?ED&MO\OCMF`GXTUNOKZZG`?R>.eXOCTZOC>dZUO 0OCTUG`?>^cX[<D&>dZG IKGXMRMOC_dDmZUG`ICG9>?RMz>]G.\@GH\@?zT?R OCTU?F`O0>dZG =MzQ%G&ZO0>@C?ED&MO\OCM>@G\G D D9>]Ijgza O0NUNPG`>.[@MRMG Q%OCT MOQ@TGXQ@TU?ROCZU `\OCMM:a D&FHQ@M?RS<ICD&ZG9TUOG9Q%OCTjD&C?G9><D&MO [@MzTUO0N?ENZUG9TUO\@D?R>?R>]_9TUO0NUNPG`e.?zNPGX>@G cx[]?r>]\@? t»o9k]q<o0t MD`MOC_9_XO\?7~g@F D&ZPZUTUDfeXOCTjND&ZGo\@D kω ŒOCT MEDVMOC_X_9O\?ˆ?TjIjg@g@G& Y\O0MRMOyIKGXTTUOC>dZU? D9Ml>@G\G DHMDHICG9TUTO0>XZUO [@_X[]D&MOD&MMD`IKGXTTUOC>dZO = V kω = m ¼
V R0k 0kΩ kω a + b V V R0k k Ω ŒOCT"MEDMOC_9_XO\? ~g]fmedzo0>]np?g9>]onp[]m]tuo0n?npzgxto \@D cx[]?r>]\@?]q]d9t?]d 0kΩ V R0k = m 0kΩ = 0V \?NOC_X>@GH?R>]\@?I0DmZO?> S]_9[@TjD ICG9>HMOIKGX>deXOC>@0?RGX>@? ŒOCTMED MOC_X_9Oo\?7ˆ?RTjIjg@g@G9 L\O0MRMOZUOC>]N?RGX>@?NP[@MMED F D&_9M?ED IKG9FHQ%GXNPZUD \@D9M$>]G.\@G \?7T?R OCTU?RFHO0>XZUG]k%\@D&M$>@G\GnWYOo\]D&M>]G.\@G D N? g]d Ijg@OMEDoZUOC>]N?G9>@OD&?$ICD&Q]?z\OCMzTUO0N?ENZUG9TUO\@D^p0½n?R> []NUIK?RZUD D9MRMba D9FHQ@MR?RS<I0DmZGXTOG9Q%OCTjD&0?RGX>]D&MO Q<D&TU? D k]gmedexoctugy¾ r9t DHIKGXTTUOC>dZUO? cd[@?>]\? V R0k = 0V kω = 0m pcw< } $DVQ%G&ZUOC>@sD \?ENN?RQ<DmZUD { Gme.eXOCTUG`DXNNG9TUW@?RZUDX,\@D9MlTOsNP?ENZUG9TUONUD&Tj `cx[]?r>]\@? P RO = kω (0m) = 0 00 0 6 W = 00mW =M7_XOC>@O0TUD&ZGXTOy\?7ZUOC>]N?RGX>@Ò OCTUG9_XDH[]>]DxICG9TUTO0>dZOo\? F Ò cd[@?>]\?bklgxnunoctuefd&zgnijg@ò MED IKGXTTUOC>dZUOoICD9MICG9MEDmZUDnOoMEDnZUOC>]N?RGX>@O \OCM_9OC>]OCTjDmZGXTONPO0_9[@GX>@G`[@>]D IKGX>.e9OC>]C?G9>@O\OC?l_XOC>@O0TUD&ZGXT?bkNP?lg]DHIjg@OMED`Q<G9ZO0>@0D`_9O0>@OCTjDmZjD Q<D&TU? D] P G = V m = mw "a D&FHQ@M?RS<ICD&ZG9TUÒ G9Q%OCTjD&C?G9><D&MO [@>h\g9q@q]?rg^w@?q<gxmrg^?>lic[@?"med Q<GXTPZjDqp \@DmZjD^\@D&?"\[]Ò FHGXTUNOKZZ?"\?(?>@_9TUO0NUNG]klFHOC>dZTUO MDYQ<GXTPZjD G9TUF DmZjDJ\@D&M,F`GXTUNOKZZGY\?}[]NUIK?RZUDJOx\@D&M,F`GXTUNOKZZGY\?,F D9NUND $D^Q<G9ZO0>@0DJO0TGX_XD&ZUD^\@D&MMED^Q<GXTPZjD p >.[@MMD]k$?> cd[]d&>dzgnng9>]g >d[]mrmoon?dhmednikgxttuoc>dzuoijg]oymd`zuoc>]n?g9>@oon[^zud9mrooq<gxtpzjd DHQ%G&ZO0>@0DnOCTUG9_XD&ZUD`\@D&MMED Q<GXTPZjD \@D&ZUDn\@D9MzQ@TUG\G&ZZG \?<ZOC><NP?G9>@OOIKGXTTUOC>dZUO}FH?ENP[]TUD&ZOICG9> [@>]DoIKG9>.eXOC>@0?RGX>@O\OC?%_9O0>@OCTjDmZUG9TU? Œ7O0T,I0D&MEIKG9MED&TUO MEDQ<G9ZO0>@0DO0TGX_XD&ZUD\@D&MMba D9F`Q]MR?RS<ICD&ZGXTO IK?7NPO0TeXOcd[@?>]\?7ICD9MICG9MED&TUOMED IKGXTTUOC>dZUO[<NICOC>dZOy\@D9MN[@G FHG9TjNPOCZPZGn\@?[]NUIK?RZUD N?ED&FHG [@>]Dn OC_X_9O\?$ˆ?TjIjg@g@G& q\@ocmmrooicg9tuto0>dz? D&Mz>]G.\@G`W^G9ZPZO0>@OC><\G] out = + = m DVZO0>]N?RGX>@O\?z[]NUIK?RZUDH\O0MRMba D9FHQ@MR?RS<I0DmZGXTO {:ICD&MEIKGXMD&ZUDV?R>^Q@TUO0ICO0\@ICOC>@sDX \?l¾ r9t»µ "!$# " %#&('"'() *,+.-0/0 P OP MP = 0V ( m) = 0mW ~ZPZUOC>@?ED&FHG cd[@?r><\? E 0 Ω 9 ) Determnare l bpolo equalente d Theenn a morsett. ) S dca quale delle seguent affermazon è corretta, gustfcando la rsposta: a) l bpolo è passo, b) l bpolo è controllable n tensone. 00 Ω 0 V 0 Ω TTENZIONE: Lo solgmento dell eserczo À a rportato qu sotto
«««O %7698:<;7+ ŒOCT?M<I0D&MEIKGXMRG\O0MRMEDTUO0N?NPZO0>@0DO0cd[@?emD&MOC>dZON?]Q][@ yq@tugiko0\@octuo}?> F D&>@?OCTjD?E\OC>dZ?EICDDocX[]OCMMDNQ<OsIK?RS<ICD&ZUDQ%OCT,M:a O0NOCTjIK?C?G p\o0m IKGXF`Q]?ƒZUG G9Q@Q][@TOoQ@TGICO0\O0TOyICG9>YMED e.?dx\[]d9mroxk<[zu?rm?c0d9>]\gn[]>q_9o0>@octjdmzug9tuo\?7ng9><\@dn\?ikgxttuoc>dzoooy_9?[@>@_xoc>]\gxd&mmrg NPZOsNNG T?EN[@MƒZjDmZUG ŒOCT}?RMlICD9MICG9MGV\O0MRMEDZUOC>]N?G9>@OO0cd[@?emD&MOC>dZO N[ÁnIK?OC>dZOTU?NUD&M?RTUOD9M%emD9MRGXTO\@OCMMDoZO0>]NP?G9>]ODVed[]G&ZG?%>]G&ZUD`Ijg@ODoe.[@G9ZGoMED IKGXTTUOC>dZO \OCeXOD&ZPZUTUDfeXOCTjND9TOD9>]Ijg@O?Ml_9OC>]OCTjDmZGXTO\?zICG9TUTO0>XZUO9k.G&ZZO0>@OC>]\@G = 9 D9MROOscX[<D&C?G9>]OGXF`GX_9O0>@O0DVg]DHIKGXF`OyNG9M[@0?RGX>@O = 0 O MEDIKG9TUTUOC>dZO Ijg@ODmZZTjDfe9O0TUNUD?@TUO0N?ENZUG9TU?@\@D >.[@MRMEDNUD&Tj >.[@MMDD9>]Ijg@O MEDZOC><NP?G9>@OD9?MRGXTGI0D&Q@?{Q<O0T"MEDMRO0_9_9O \? ~g@fn OVcd[@?>]\?bk<Q%OCTMDnMRO0_9_9Oy\@?7ˆ?TUIjg]g@G& u\@ocmmdhzuoc>]n?g9>@ood9mrmedhf 0Ω D&_XMR?ED IKGXF`Q]TO0>]\OC>dZUO k<?7tuo0n?npzgxt?z\@d V 0Ω ZO0>]NP?G9>]Oy\@D p0r&t N?lG&ZZ?OC>@O Os\^?RM$_9OC>]OCTjDmZGXTO\? V eq = 0V D] ~V l=m W@?RQ%G9MG^>@G9> Q]DXNN?ReXGx?> cd[]d&>dzg?m NP[]G^IC?RTjIK[]?ƒZUG Oscd[@?RemD9MRO0>XZUO g@ocexoc>@?>hg]d [@>h_9oc>]octjdmzgxtò \?(ZUOC>]N?RGX>@O >@G9>x>.[@MRMG`Ocd[@?>]\?lMEDoN[]DVI0D&TjDmZZOCTU?ENZU?I0D>@G9>xQ]D9NUNDVNPGXMRGVQ<O0T,?M Q@TU?RFHG`OQ%OCT?M<ZUOCTUCG`cX[<D9\TjD&>dZOV{ [ZU?RM?R00D9>]\G`MROIKGX>deXOC>@0?RGX>@? \OC_XMR?[Z?MR?CsDmZUG9TU?%Q%OCTO0NQ@T?FHOCTU>@OIKG9TUTUOC>dZOOZO0>]NP?G9>]Os Wz }t,ª ~Â=M$W@?RQ%G9MG ICG9>dZTUG9MMED&W@?MRO?>^ZO0>]N?RGX>@Oy?>qcd[]D&>dZG<k]IKGXMRMOC_dD&>]\@G [@>J_9O0>@OCTjDmZUG9TUO\@?zZO0>]N?RGX>@OZTjD?$F`GXTUNOKZZ? MDxTUOKZÒ G&ZZO0>d[@ZUDxg]DxNG9M[@0?RGX>@O D&MOVGdNNOCTUemD&0?RGX>@OyQ@[@ O0NUNOCTUOy D9IC?RMFHOC>dZÒ e9o0t?rs<i0dmzud [Z?M?R00D&><\Gx?M(IK?TUIC[@?RZG O0cd[@?efD9MRO0>dZO g@ocexoc>@?>qohikgxmrmoc_dd&>]\@g [@>u_9oc>]octjdmzgxtov\?zo0>]np?g9>]ov?>qq]d9tud9mrmocmgxdx\yosnng y«nunpo0>]\g R eq 0 N?7Q%GXNUNG9>@G ICD&MEIKGXMD9TOVNP?ED I Ijg@OyIjg@O V Y»µ "!$# " %#&('"'() *,+.-0/0 E V Conoscendo l alore delle arabl assegnate sul crcuto e sapendo che l bpolo assorbe 0 W determnare la tensone e la corrente del bpolo. V V TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto Ã
%7698:<;7+ V 0W/V=0 V V V V V V LKT LKT Def. Potenza LKI 0 Rsultato ŒOCT _9?[@>@_XOCTUOD9MzTU?N[@MRZUDmZUG`N?zOsNPO0_9[@GX>@GV?lQ<D9NUNP?l?>]\?EICD&Z?z?> S]_9[@TjD@kD9Q@Q@M?I0D&>]\GHTU?NQ%OKZPZU?RemD9F`O0>dZO9 $ˆ «$ˆ «OKS<>@?R0?RGX>@Oy\?lQ%G&ZUOC>@sD $ˆ G&ZZOC>]OC>]\G?MlTU?N[@MRZUDmZUGHT?Q<GXTPZjDmZUGV>@O0MRMba [@MƒZU?RF D`S]_X[@TjD`\@OCMzW@MGICICG Y!µ »µ7 PP "!$# " %#m"'"'() *,+.-0/0 V TTENZIONE: Solgere a scelta l eserczo Ea oppure Eb Ea 6 Ω e e e ) Utlzzando l metodo dell anals nodale, determnare potenzal d nodo e, e, e rspetto al nodo d rfermento. ) determnare l alore della tensone ) determnare l alore della corrente g ) Determnare la potenza erogata dal generatore d tensone da V g 6 Ω Ω V 6 V Ω TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto Ä
«%7698:<;7+?zTU?I0DfemD&>@G`?RFHFHO0\@?D&ZUD&FHO0>XZUO9 e = V e = 6V ª?FHD9>@Ocd[@?R><\?\@D I0D&MEIKG9MED&TUO?Mz>@G\G IKGX>x?MzFHOKZUG\Gn\OC?lQ%G&ZUOC>@0?D9MR?$\?z>@G\G ( IKTU?Re.?ED&FHGVMEDH ˆ= D&Ml>@G\G e e + } 6Ω {{} Corr. R da 6Ω e Ω }{{} Corr. R da Ω + e e = 0 } Ω {{} Corr. R da Ω e 6 6 + e + e 6 = 0 e + + = } DVZUOC>]N?RGX>@O V e = V \@D&ZUDH\@D&MMED`\@?ƒ OCTUOC>@sDH\OC?zQ%G&ZUOC>@0?D9MR?z\@OCMz>@G\G Oy\O0Ml>@G\GJp,ŒOCTI0D&MEIKGXMD9TOMDHIKGXTTUOC>dZUO V = e e = ( 6) = 8V g NICT?e.?D9F`G`[@>]D $ˆ D&Mz>@G\G^p \@DHIK[@? g + e e 6Ω + e e 6Ω = 0 ( V V g = 6Ω + + 6 ) = (. + 0.) = 6Ω ¹?,>@G&ZU? Ijg@O O MED ZO0>]N?RGX>@On\?p t NG9>@G^MOC_dDmZOH>@O0MRMEDJ>@GdNZUTUD TUOKZUOn\@D^[@>]DJICG9>.e9O0>@C?G9>@O \O0_9M? cd[@?r><\? D`Q%G&ZUOC>@sDH ª~Æ g \@D9Ml_9O0>@OCTjDmZUG9TUO\@D^p t ND9TU («$ = =ÅzÅ («~ª =O P G = V I = ( ) V = W Y!ºÇ.»µ $P $H!$#. " #m('"'") *,+.-0/0 TTENZIONE: Solgere a scelta l eserczo Ea oppure Eb Eb kω 0 kω ) Determnare la corrente he percorre l resstore R o e la potenza da esso dsspata. ) Determnare la potenza erogata dal generatore d tensone ) Determnare la potenza erogata dall amplfcatore operazonale 0 V R o = kω TTENZIONE: Lo solgmento dell eserczo a rportato qu sotto È
%7698:<;7+ D^NG9M[@C?G9>@O \OCMZU[ZPZUG^O0cd[@?efD9MRO0>dZO Dxcd[@O0MRMED O0NQ<GdNZjD Q%OCT?M"IKGXFHQ@?ƒZUG kznuicd9md9>]\gxz[zzo MOVZUOC>]N?G9>@?OHMRO ICG9TUTO0>XZU?(\?([@> DmZZG9TUO ¼ { zoq%g&zuoc>@0oynd9tud9>@>@g`cx[]?r>]\@?ni0d&medmzuo\@?z[@> DmZZG9TUO 9¼ ~ZPZUOC>@?ED&FHG cd[@?r><\? ps V R = 0V, \]DVIC[@? V out = 00V pcw< = 00m P RO = 0000mW = 0W out = m, \@D`IK[]? P G = 00mW P OP MP = 0m 00V = W p0r